一个简单的打字练习程序

文章作者 100test 发表时间 2007:03:10 17:29:24
来源 100Test.Com百考试题网

类似于学习机上的指法练习程序，简单而实用
#include
main()
{
int x,y,i,j.
unsigned int Timer.
char ch.
char key.
char *kb[]={"Q W E R T Y U I O P [ ]","A S D F G H J K L . ’","Z X C V B N M , . /"}.
long AllCounter=0,RightCounter=0,FalseCounter=0.
time_t t.
int fun_Esc().
srand((unsigned)time(&.t)).
clrscr().
gotoxy(18,1).
printf("%s\n",kb[0]).
gotoxy(20,3).
printf("%s\n",kb[1]).
gotoxy(22,5).
printf("%s\n",kb[2]).
gotoxy(11,25).
for(i=0.i<60.i )
{
printf("=").
}
gotoxy(1,1).
printf("AllCh: %ld\nRight: %ld\nFalse: %ld",AllCounter,RightCounter,FalseCounter).
printf("\n\n").
printf("Esc to exit").
printf("\n").
printf("Enter to pause").
gotoxy(26,12).
printf("* * * * * * * * * * * * * * *").
gotoxy(26,13).
printf("* Press any key to start! *").
gotoxy(26,14).
printf("* * * * * * * * * * * * * * *").
gotoxy(51,13).
if(getch()==27)
{
if(fun_Esc()==1)
{
clrscr().
exit(0).
}
}
gotoxy(23,12).
printf(" ").
gotoxy(23,13).
printf(" ").
gotoxy(23,14).
printf(" ").
lab_start:
y = 6.
Timer = 100000.
i = rand()%3.
j = rand()%(12-i).
ch = kb[i][j*4].
x = 18 i*2 j*4.
while(y<=24)
{
if(kbhit())
{
key = getch().
if(key==ch || key==ch 32)
{
ch = ’*’. Timer = 1000.
}
else if(key==27)
{
if(fun_Esc()==1)
{
clrscr().
exit(0).
}
}
else if(key==’\r’)
{
gotoxy(x,y-1).
printf(" ").
gotoxy(28,13).
printf("Press any key to continue").
getch().
gotoxy(28,13).
printf(" ").
}
else
{
FalseCounter .
}
}
if(y>6)
{
gotoxy(x,y-1).
printf(" ").
}
gotoxy(x,y).
printf("%c",ch).
gotoxy(1,1).
printf("AllCh: %ld\nRight: %ld\nFalse: %ld",AllCounter,RightCounter,FalseCounter).
delay(Timer).
y .
}
AllCounter .
if(ch == ’*’)
{
RightCounter .
}
goto lab_start.
}
int fun_Esc()
{
int key = ’#’.
gotoxy(24,12).
printf("* * * * * * * * * * * * * * * * *").
gotoxy(24,13).
printf("* Are you sure to exit? (Y/N) *").
gotoxy(24,14).
printf("* * * * * * * * * * * * * * * * *").
gotoxy(51,13).
while(key!=’Y’ &.&. key!=’y’ &.&. key!=’N’ &.&. key!=’n’)
{
key = getch().
if(key==’Y’ || key==’y’)
{
return 1.
}
if(key==’N’ || key==’n’)
{
gotoxy(24,12).
printf(" ").
gotoxy(24,13).
printf(" ").
gotoxy(24,14).
printf(" ").
return 0.
}
}
}