C程序开发经典实例之7

文章作者 100test 发表时间 2007:04:06 21:29:44
来源 100Test.Com百考试题网

计算机等级考试训练软件《百宝箱》

【程序61】
题目：打印出杨辉三角形（要求打印出10行如下图）
1.程序分析：
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
2.程序源代码：
main()
{
int i, j.
int a[10][10].
printf("\n").
for(i=0. i<10. i )
{
a[i][0] = 1.
a[i][i] = 1.
}
for(i=2.i<10.i )
for(j=1.j<10. j )
a[i][j] = a[i-1][j-1] a[i-1][j].
for(i=0. i<10. i )
{
for(j=0.j<=i.j )
printf("]", a[i][j]).
printf("\n").
}
}

【程序62】
题目：学习putpixel画点。
1.程序分析：
2.程序源代码：
#include "stdio.h"
#include "graphics.h"
main()
{
int i, j, driver = VGA, mode = VGAHI.
initgraph(&.driver, &.mode, "").
setbkcolor(YELLOW).
for(i=50. i<=230. i =20)
for(j=50. j<=230. j )
putpixel(i, j, 1).
for(j=50. j<=230. j =20)
for(i=50. i<=230. i )
putpixel(i, j, 1).
}

【程序63】
题目：画椭圆ellipse
1.程序分析：
2.程序源代码：
#include "stdio.h"
#include "graphics.h"
#include "conio.h"
/* 欢迎访问 C Builder研究 - www.ccrun.com */
main()
{
int x = 360, y = 160, driver = VGA, mode = VGAHI.
int num=20, i.
int top, bottom.
initgraph(&.driver, &.mode, "").
top = y - 30.
bottom = y - 30.
for(i=0. i {
ellipse(250, 250, 0, 360, top, bottom).
top -= 5.
bottom = 5.
}
getch().
}

【程序64】
题目：利用ellipse and rectangle 画图。
1.程序分析：
2.程序源代码：
#include "stdio.h"
#include "graphics.h"
#include "conio.h"
main()
{
int driver = VGA, mode = VGAHI.
int i, num = 15, top = 50.
int left = 20, right = 50.
initgraph(&.driver, &.mode, "").
for(i=0. i {
ellipse(250, 250, 0, 360, right, left).
ellipse(250, 250, 0, 360, 20, top).
rectangle(20 - 2 * i, 20 - 2 * i, 10 * (i 2), 10 * (i 2)).
right = 5.
left = 5.
top = 10.
}
getch().
}

【程序65】
题目：一个最优美的图案。
1.程序分析：
2.程序源代码：
#include "graphics.h"
#include "math.h"
#include "dos.h"
#include "conio.h"
#include "stdlib.h"
#include "stdio.h"
#include "stdarg.h"
#define MAXPTS 15
#define PI 3.1415926
struct PTS
{
int x, y.
}.
/* 63 63 72 75 6E 2E 63 6F 6D */
double AspectRatio = 0.85.
void LineToDemo(void)
{
struct viewporttype vp.
struct PTS points[MAXPTS].
int i, j, h, w, xcenter, ycenter.
int radius, angle, step.
double rads.
printf(" MoveTo / LineTo Demonstration" ).
getviewsettings( &.vp ).
h = vp.bottom - vp.top.
w = vp.right - vp.left.
xcenter = w / 2. /* Determine the center of circle */
ycenter = h / 2.
radius = (h - 30) / (AspectRatio * 2).
step = 360 / MAXPTS. /* Determine # of increments */
angle = 0. /* Begin at zero degrees */
for(i=0. i {
rads = (double)angle * PI / 180.0. /* Convert angle to radians */
points[i].x = xcenter (int)( cos(rads) * radius ).
points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio ).
angle = step. /* Move to next increment */
}
circle( xcenter, ycenter, radius ). /* Draw bounding circle */
for(i=0. i {
for(j=i. j {
moveto(points[i].x, points[i].y). /* Move to beginning of cord */
lineto(points[j].x, points[j].y). /* Draw the cord */
}
}
}
main()
{
int driver, mode.
driver = CGA. mode = CGAC0.
initgraph(&.driver, &.mode, "").
setcolor(3).
setbkcolor(GREEN).
LineToDemo().
}