【程序61】
题目:打印出杨辉三角形(要求打印出10行如下图)
1.程序分析:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
2.程序源代码:
以下是引用片段:
main()
{int i,j.
int a[10][10].
printf("/n").
for(i=0.i<10.i )
{a[i][0]=1.
a[i][i]=1.}
for(i=2.i<10.i )
for(j=1.j a[i][j]=a[i-1][j-1] a[i-1][j].
for(i=0.i<10.i )
{for(j=0.j<=i.j )
printf("]",a[i][j]).
printf("/n").
}
}
【程序62】
题目:学习putpixel画点。
1.程序分析:
2.程序源代码:
以下是引用片段:
#include "stdio.h"
#include "graphics.h"
main()
{
int i,j,driver=VGA,mode=VGAHI.
initgraph(&.driver,&.mode,"").
setbkcolor(YELLOW).
for(i=50.i<=230.i =20)
for(j=50.j<=230.j )
putpixel(i,j,1).
for(j=50.j<=230.j =20)
for(i=50.i<=230.i )
putpixel(i,j,1).
}
【程序63】
题目:画椭圆ellipse
1.程序分析:
2.程序源代码:
以下是引用片段:
#include "stdio.h"
#include "graphics.h"
#include "conio.h"
main()
{
int x=360,y=160,driver=VGA,mode=VGAHI.
int num=20,i.
int top,bottom.
initgraph(&.driver,&.mode,"").
top=y-30.
bottom=y-30.
for(i=0.i{
ellipse(250,250,0,360,top,bottom).
top-=5.
bottom =5.
}
getch().
}
【程序64】
题目:利用ellipse and rectangle 画图。
1.程序分析:
2.程序源代码:
以下是引用片段:
#include "stdio.h"
#include "graphics.h"
#include "conio.h"
main()
{
int driver=VGA,mode=VGAHI.
int i,num=15,top=50.
int left=20,right=50.
initgraph(&.driver,&.mode,"").
for(i=0.i{
ellipse(250,250,0,360,right,left).
ellipse(250,250,0,360,20,top).
rectangle(20-2*i,20-2*i,10*(i 2),10*(i 2)).
right =5.
left =5.
top =10.
}
getch().
}
【程序65】
题目:一个最优美的图案。
1.程序分析:
2.程序源代码:
以下是引用片段:
#include "graphics.h"
#include "math.h"
#include "dos.h"
#include "conio.h"
#include "stdlib.h"
#include "stdio.h"
#include "stdarg.h"
#define MAXPTS 15
#define PI 3.1415926
struct PTS {
int x,y.
}.
double AspectRatio=0.85.
void LineToDemo(void)
{
struct viewporttype vp.
struct PTS points[MAXPTS].
int i, j, h, w, xcenter, ycenter.
int radius, angle, step.
double rads.
printf(" MoveTo / LineTo Demonstration" ).
getviewsettings( &.vp ).
h = vp.bottom - vp.top.
w = vp.right - vp.left.
xcenter = w / 2. /* Determine the center of circle */
ycenter = h / 2.
radius = (h - 30) / (AspectRatio * 2).
step = 360 / MAXPTS. /* Determine # of increments */
angle = 0. /* Begin at zero degrees */
for( i=0 . irads = (double)angle * PI / 180.0. /* Convert angle to radians */
points[i].x = xcenter (int)( cos(rads) * radius ).
points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio ).
angle = step. /* Move to next increment */
}
circle( xcenter, ycenter, radius ). /* Draw bounding circle */
for( i=0 . ifor( j=i . jmoveto(points[i].x, points[i].y). /* Move to beginning of cord */
lineto(points[j].x, points[j].y). /* Draw the cord */
} } }
main()
{int driver,mode.
driver=CGA.mode=CGAC0.
initgraph(&.driver,&.mode,"").
setcolor(3).
setbkcolor(GREEN).
LineToDemo().}
src="/ncre2/js/wxgg.js">